Construction of Arc Tangent to Any Two Lines
Figure 4-34 shows a method that can be used regardless of the size of the angle formed by the
lines. Again AB equals the given radius of the arc, and the problem is to draw an arc with radius
equal to AB, tangent to CD and EF. Draw GH parallel to CD and at a distance from CD equal to the given radius of the arc. Draw IJ parallel to EF and also at a distance equal to the given radius of the arc. The point of intersection between GH and IJ (P) is the center of the circle of which an arc of the given radius is tangent to CD and EF.